Starting from his house, Ali walks 3 km north, then 4 km east to reach the market. What is the shortest distance between his house and the market?
Difficulty: Medium
About this MCQ
This Medium Analytical Reasoning MCQ checks one syllabus fact.
The question is: “Starting from his house, Ali walks 3 km north, then 4 km east to reach the market. What is the shortest distance between his house and the market?”
The accepted answer is B. 5 km. Using the Pythagorean theorem on the 3 km and 4 km legs: the straight-line distance is the square root of (3^2 + 4^2) = 5 km.
- A. 4 km
Why not A: “4 km” is not correct. The accepted answer is B. 5 km. Using the Pythagorean theorem on the 3 km and 4 km legs: the straight-line distance is the square root of (3^2 + 4^2) = 5 km.
- B. 5 km ✓
- C. 7 km
Why not C: “7 km” is not correct. The accepted answer is B. 5 km. Using the Pythagorean theorem on the 3 km and 4 km legs: the straight-line distance is the square root of (3^2 + 4^2) = 5 km.
- D. 6 km
Why not D: “6 km” is not correct. The accepted answer is B. 5 km. Using the Pythagorean theorem on the 3 km and 4 km legs: the straight-line distance is the square root of (3^2 + 4^2) = 5 km.
Correct answer
B. 5 km
Explanation
Using the Pythagorean theorem on the 3 km and 4 km legs: the straight-line distance is the square root of (3^2 + 4^2) = 5 km.
Source: Analytical Reasoning Official FPSC/NTS/PPSC-Style Reference Guide
Tags: FPSC, PPSC, logical reasoning, analytical reasoning, aptitude, NTS
Submitted by: MCQsHub Editorial
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